In a data distribution the first quartile, median and mean are 30.8,48.5,42.0 respectively. If the coefficient skewness is - 0.38,
1.Find the appropriate value of the third quartile
2.Find the appropriate value of the variance
Answers
Given : In a data distribution, the first quartile, the median and the mean are 30.8, 48.5 and 42.0 respectively. the coefficient skewness is -0.38
To find : value for the third quartile?
Solution:
Q1 = 30.8
Median Q2 = 48.5
Mean = 42
Mean < median hence -ve coefficient skewness
coefficient skewness = (Q1 + Q3 - 2Q2)/(Q3 - Q1)
-0.38 = (30.8 + Q3 - 2(48.5) )/(Q3 - 30.8)
=> -0.38Q3 + 11.704 = 30.8 + Q3 - 97
=> 1.38Q3 = 77.904
=> Q3 = 56.45
value for the third quartile = 56.45
3IQR = 4SD
IQR = 56.45 - 30.8 = 25.65
SD = 3(25.65)/4 = 19.24
Variance = SD² = 370
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