Question

In a dc motor the developed torque is 200 Nm at 600 rpm. At 500 rpm the motor torque would be?

Answer 1

$\pink{\huge{\underline{\star\: Solution\: \star}}}$

T = Torque (in N-m)
N = Speed (in rpm)

$T_1 = 200\: Nm \\ N_1 = 600 \:rpm \\ T_2 = ? \\ N_2 = 500 \: rpm$

$T_1 \times N_1 = T_2 \times N_2$

$200\times 600 = T_2 \times 500 \\\implies T_2 =\frac{200\times600}{500} \\\implies T_2 = \frac{120000}{500} \\ \implies T_2 = 240 \: Nm$

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$\pink{\boxed{ T_2 = \: 240\: Nm}}$