Question

in a Den there are rabbit and pheasant.In between them there are 35 heads and 98 legs find the number of rabbits

Answer 1

Hi friend,
Find the solution below!

Answer 2

Answer:

The number of rabbits are 14

Step-by-step explanation:

Let x be the no. of rabbits and y be the no. of pheasants .

We are given that there are 35 heads

So, x+y=35 --1

No. of legs of 1 rabbit = 4

No. of legs of x rabbits = 4x

No. of legs of 1 pheasant = 2

No. of legs of y pheasant = 2y

We are given that  there are 98 legs

So, 4x+2y = 98 --2

Solve 1 and 2

Substitute the value of x from 1 in 2

$4(35-y)+2y = 98$

$140-4y+2y = 98$

$140-2y = 98$

$140-98 =2y$

$42=2y$

$\frac{42}{2} =y$

$21 =y$

Substitute the value of y in 1

x+21=35

x = 35-21

x = 14

Hence The number of rabbits are 14