Question

in a den there are rabbits and pheasant. tgere are 35 heads and 98 feet in total. find the number of rabbits and pheasants

Answer 1

Nice question!

Let ‘r’ be the number of rabbits and ‘p’ be the number of pheasants.

Given that,there are 35 heads.

We know that both rabbits and pheasants have a single head so:-

$= > r + p = 35$

Now it is given that,there are 98 feet total.
We know that rabbits have 4 feet and pheasants have 2.

So:-

$4r + 2p = 98$

Now that we have two equations,let us solve it by elimination method.

Multiply 2 on both the sides.....

$= > 2r + 2p = 70.....(1)$

$= > 4r + 2p = 98......(2)$

Now,on solving equation 1 and 2,we get:-


$= > 4r + 2p - (2r + 2p) = 98 - 70$

$= > 4r + 2p - 2r - 2p = 28$

Here +2 and -2 got cut ,and 4r-2r is equal to 2r.

$= > 2r = 28$

$= > r = 14$

So from the above calculation,there are 14 rabbits and 35-14=21 pheasants.

Answer 2

Answer:

Refers to the attachment....