In a design made from tiles each of dimensions 40cm by 60cm,find the ratios of:
a)the perimeter of shaded portion to the perimeter of the whole design.
b)the area of the shaded portion to the area of the unshaded portion
Answers
★Given :
- Length of tile = 60cm
- Breadth of tile = 40cm
★To find :
- The perimeter of shaded portion to the perimeter of the whole design.
- The area of the shaded portion to the area of the unshaded portion
★Solution :
Let us take 1 tile as 1 unit.
Now,
For the shaded portion :
- Length = 3units
- Breadth = 2units
Perimeter = 2(l+b)
=2(3+2)
= 10 units
Therefore,
- Perimeter of shaded portion = 10units
Area = l×b
= 3(2)
= 6sq units
Therefore,
- Area of shaded portion = 6 sq. units
For the whole design :
- Length = 5units
- Breadth = 4units
Perimeter = 2(l+b)
=2(5+4)
= 18units
Therefore,
- Perimeter of whole design = 18units
Area = l×b
= 5(4)
= 20sq units
Therefore,
- Area of whole design = 20 sq. units
And,
Area of unshaded portion = Total area - Area of the shaded portion
→20 - 6
→ 14 sq. units
~To find Ratio of perimeter of the shaded portion to the perimeter of the whole design :
→Perimeter of shaded portion/Perimeter of whole design
→10/18
→5/9
→5 : 9
~To find Ratio of area shaded portion to the area of unshaded portion :
→Area of shaded portion/Area of unshaded portion
→ 6/14
→ 3/7
→ 3 : 7