In a differential wheel and axle the diameter
of the effort wheel is 400 mm. The radii of
the axles are 150 mm and 100 mm
respectively. The diameter of the rope is
10mm. Find the load which can be lifted
by and effort of 25N assuming the efficiency
of the machine to be 84%.
Answers
Given : In a differential wheel and axle the diameter of the effort wheel is 400 mm. The radii of the axles are 150 mm and 100 mm
To Find : the load which can be lifted by and effort of 25N assuming the efficiency of the machine to be 84%.
Solution:
Velocity Ratio in differential axle = 2 * Dia wheel / ( difference in axle dia)
= 2 * 400 / 2( 150 - 100)
= 8
an effort of 25N lifts
Equivalent Effort = Effort * Velocity Ratio
=> Equivalent Effort = 25 * 8 = 200N
200 N Equivalent Effort lifts a load of x N
=> efficiency of machine. = (x/200) * 100 = x/2
x/2 = 84
=> x = 168
Hence 168 N load can be lifted
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