Question

in a discharge tube the number of hydrogen ions interacting across a cross section per second is 1 into 10 power 18 while the number of electrons drifting in the opposite direction across another cross section is 2.7 into 10 power 18 per second. if the supply voltage is 230 volts. Then effective resistance of the tube is

Answer 1

Effictive resistance=V/I

where v=voltage

I is current through cross section

I=Q/T

=(Np+Ne)*e/t

=(2.7*10^18)+(1*10^18)/1

=0.592A

Therefore effictive resistance=V/I

230/0.592=3.9*10^2ohms

Answer 2

Answer:

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