Chemistry, asked by JortalCombat, 11 months ago

In a discharge tube, there are only two hydrogen atoms. If the electrons in both atoms are de-exciting from
4th orbit, the minimum and maximum number of spectral lines should respectively be
(1) 1,4
(2) 4,1
(3) 3, 4
(4) 1,6

Answers

Answered by khushi07yadav2004
2

Explanation:

min will be 4 to 1

max 4to 3 , 3 to 2 , 2to1 and 3 to 1

we will not count 4 to 3 again as we have already counted that .

this is teacher approved ans even I was struggling with this que

so, final ans is A

Attachments:
Answered by soniatiwari214
0

Answer:

The minimum number of spectral lines is 1 and the maximum number of spectral lines is 4, as the electrons in both atoms are de-exciting from

4th orbit.

Explanation:

When the spectral line will move directly from the 4th orbit to the ground state, i.e, the 1st orbit, the number of spectral lines is minimum. Here, the number of spectral lines is 1. Hence, the minimum number of spectral lines is 1.

But when the spectral line will move from the 4th orbit to the 3rd orbit, the 3rd orbit to the 2nd orbit, the 2nd to 1st orbit, and the 4th to 2nd orbit, the number of spectral lines is maximum. Here, the number of spectral lines is 4. Hence, the maximum number of spectral lines is 4.

Hence, the minimum and the maximum number of spectral lines should respectively be 1 and 4. Hence, the correct option is (1) 1,4.

#SPJ2

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