Question

In a division problem, quotient is 7x + 3y, divisor is 2x - 5y and -3y² is the

remainder. Find the dividend​

Answer 1

Explanation:

DIVIDEND = (DIVISOR ×QUOTIENT)+REMAINDER

x =[ (2x-5y )×(7x+3y)]+(-3y^2)

x= [2x(7x+3y)-5y(7x+3y)]+(-3y^2)

x= 14x^2 + 6xy - 35xy + 15y^2 - 3y^2

x= 14x^2 - 29xy + 12y^2

thus,the dividend is 14x^2 - 29xy +12y^2.

HOPE IT WILL HELP YOU..:-)..THANK YOU

Answer 2

Answer:

Dividend = 14x²-29xy-18y²

hope it helps you✌