Question

in a Division problem the divisor is(a2 +2a_1), quotient is (5a _14) and remainder is (35a_17) fine the dividend . For class 8​

Answer 1

$\sf{Divisor => a^2 + 2a - 1}$

$\sf{Quotient => 5a - 14}$

$\sf{Remainder => 35a - 17}$

Using Division algorithm

$\sf{Divided = Divisor × Quotient + Remainder}$

$\sf{Divided = a^2 + 2a - 1 × ( 5a - 14 ) + 35a - 17}$

$\sf{=> 5a(a^2 + 2a - 1) -14( a^2 + 2a - 1) + 35a - 17}$

$\sf{=> 5a^3 + 10a^2 - 5a - 14a^2 - 28a + 14 + 35a - 17}$

$\sf{=> 5a^3 + 10a^2 - 14a^2 - 5a - 28a + 35a + 14 - 17}$

$\sf{=> 5a^3 - 4a^2 + 2a - 3}$

Therefore, Dividend is $\sf{5a^3 - 4a^2 + 2a - 3}$