In a division sum,the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 2 to the thrice of remainder.the dividend is..?
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Hi ,
the remainder = r = 6
Let the Quotient = q
Divisor = d = 5q ---( 1 )
d = 3r + 2 -----( 2 )
According to the problem given ,
( 1 ) = ( 2 )
5q = 3r + 2
5q = 3 × 6 + 2
5q = 18 + 2
5q = 20
q = 20 / 5
q = 4
Put q = 4 in equation ( 1 ) , we get
d = 5q
d = 5 × 4 = 20
By division algorithm
Dividend = divisor × quotient + remainder
= d × q + r
= 20 × 4 + 6
= 80 + 6
= 86
I hope this helps you.
:)
the remainder = r = 6
Let the Quotient = q
Divisor = d = 5q ---( 1 )
d = 3r + 2 -----( 2 )
According to the problem given ,
( 1 ) = ( 2 )
5q = 3r + 2
5q = 3 × 6 + 2
5q = 18 + 2
5q = 20
q = 20 / 5
q = 4
Put q = 4 in equation ( 1 ) , we get
d = 5q
d = 5 × 4 = 20
By division algorithm
Dividend = divisor × quotient + remainder
= d × q + r
= 20 × 4 + 6
= 80 + 6
= 86
I hope this helps you.
:)
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