Question

In a does, there are 36 children 1/4 are sick and 1/3 are out on an exhibition. How many children are left

Answer 1

$\sf \purple{ \fbox{ \underline{ Question :-}}}$

In a does, there are 36 children 1/4 are sick and 1/3 are out on an exhibition. How many children are left.

$\sf \purple{ \fbox{ \underline{ Given :-}}}$

⇒ Total no. of Children = 36

⇒ Children who are sick =

       $36 \times \frac{1}{4} = 9$

   

⇒ Children who are out on a exhibition =

    $36 \times \frac{1}{3} = 12$

$\sf \purple{ \fbox{ \underline{ To Find :-}}}$

⇒ No. of Children left.

$\sf \purple{ \fbox{ \underline{ Solution :-}}}$

⇒ Total No. Of Children - ( No. of Children Sick + No. of Children Out for exhibition )

→ 36 - ( 9 + 12 )

→  36 - 11

→ 25

Answer 2

$\sf{Answer}$

★Step by step explanation:-

★Given:-

Total children = 36

No.of children are sick :- 1/4th children

No.of children are out on a exhibition :- 1/3rd children

★To find :-

How many children are left ?

★Solution★

Total no.of children are sick = $\sf\dfrac{1}{14}$×36 = 9

Total no.of children are sick = 9

Total no.of children out of exhibition = $\sf\dfrac{1}{3}$×36 = 12

Total no.of children out of exhibition = 12

Total of no.of children are left = total no.of children -(total no.of children are sick + total no.of children out of exhibition)

Total of no.of children are left = 36-(9+12)

Total of no.of children are left = 36-21

Total of no.of children are left = 15

So, the answer is 15