Physics, asked by resharo2308, 11 months ago

In a double slit interference experiment, the maximum intensity of light would be
times that of the single slit experiment.
(A) same (B) twice (C) four times (D) half

Answers

Answered by balajidevaraj007
1

A) same

Explanation:

bcz there is no advantage of using double slit but if we close one slit we get clear image

Answered by aryansuts01
0

Answer:

Concept:

In physics, interference refers to the combined result of two or more wave trains travelling along intersecting or converging trajectories. The result is the result of adding the individual wave amplitudes at each place that is influenced by multiple waves. A wave of greater, lower, or the same amplitude is created when two waves merge through interference by combining their displacements at all points in space and time. The act of obstructing or hindering is what is meant by the term of interference. A road detour is an example of an interference. Interference is a phenomena in which two waves are superimposed to create a subsequent wave with a larger, smaller, or identical amplitude. The combined amplitude of all individual waves occurs when the peak of one wave crosses the crest of another wave with the same frequency at the same location.

Given:

The maximum light intensity in a double slit interference experiment would be multiplied by that of a single slit experiment.

(A) same

(B) twice

(C) four times

(D) half

Find:

find the right response to the provided question's inquiry.

Answer:

in the double-slit experiment

I_{net} =I_{1} +I_{2} +2\sqrt{I_{1}I_{2} cos }ϕ

When

I_{1} =I_{2}, and  cosϕ = +1

we get

I_{max} =4I_{1}

the double-slit interference's peak intensity

=4times

The ratio of amplitude addition and subtraction can be used to calculate the greatest and minimum intensity resulting from the superposition of two waves. The requirements for maximum intensity are the same whether there are two or more slits, however with many slits, the maximum intensity is highly sharp and narrow, offering the high resolution required for spectroscopic applications. In an interference pattern, the lines with the lowest intensity are referred to as the black fringe. For this, the phase difference must have a value that is an odd multiple of ϕ.

#SPJ3

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