In a drawing competition the winner gets ₹200 and all other participants(who do not win) gey ₹ 50. In competition, there were more than one winner and ₹ 4500 was distributed as the prize money. Find the total number of winner. If the total number of participants were 60.
Answers
Answer:
Let x be the number of the winners. So, the number of participants who does not win (63−x).
Prize money given to x winners = Rs. (100×x)= Rs. 100x
and prize money given to (63−x) participants = Rs. 25(63−x)
Given, total prize money distributed = Rs. 3000
∴100x+25(63−x)=3000
⇒4x+(63−x)=120 ...[On dividing both sides by 25]
⇒3x+63=120
⇒3x=120−63 ...[Transposing 63 to RHS]
⇒3x−57⇒x=
3
57
=19
∴ The number of winners is 19.
Step-by-step explanation:
Let x be the number of winners.
Then the number of participants who do not win is given as (60 – x)
The prize money given to x winners = Rs ( 200x)
The prize money given to (60 – x) participants is = Rs 50(60 – x)
According to the given data, the total prize money distributed = Rs 4500
Therefore, 200x + 50(60 – x) = 4500
take 5 or 50 as common
you will get the value of X
x = ____
Therefore, the number of winners is 19.