Question

In a ds DNA, if A=120, T=120, G=80 and C=80. How many base pairs are possible in it?​

Answer 1

BASES= 120+120+80+80= 400

BASE PAIR= 400/2= 200

Answer 2

We know that there are four bases in DNA, adenine(A), guanine (G), thymine (T), and cytosine (C).  

Given, $A=120, T=120, G=80\ and\ C=80$

Now, we know the nitrogen-containing bases adenine (A) and thymine (T)couple together; and cytosine (C) and guanine (G) couple together under normal conditions. The structure of DNA is created by the binding of these base pairs.

$\therefore$ A and T will form 120 pairs

$\therefore$ G and C will form another 80  pairs.

Total no. of pairs $=120+80=200\ pairs$

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