Science, asked by nehadevi14, 10 months ago

in a elactiric circuit two resistire of 2 ohm and 4 ohm respectively areconnected in series to a 6V battery . the hear dissipated by te the 4 ohm resister in a 5 second will be :

Answers

Answered by tejasgupta
0

Answer:

20 J

Explanation:

We know that the total resistance in a series connection is given by simply adding up the various resistances.

So, here, total resistance, R = 2 + 4 = 6 ohm

Voltage, V = 6 V

So, Current, I = V/R = 6/6 = 1 A

In a series connection,

  • Voltage gets distributed
  • Current remains the same

Resistance of 4 ohm resistor = 4 ohm

Current through it = I = 1 A

Time, t = 5 s

By Joules law of heating,

H = I*I*R*t = 1 * 1 * 4 * 5 = 20 J

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