in a elactiric circuit two resistire of 2 ohm and 4 ohm respectively areconnected in series to a 6V battery . the hear dissipated by te the 4 ohm resister in a 5 second will be :
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Answer:
20 J
Explanation:
We know that the total resistance in a series connection is given by simply adding up the various resistances.
So, here, total resistance, R = 2 + 4 = 6 ohm
Voltage, V = 6 V
So, Current, I = V/R = 6/6 = 1 A
In a series connection,
- Voltage gets distributed
- Current remains the same
Resistance of 4 ohm resistor = 4 ohm
Current through it = I = 1 A
Time, t = 5 s
By Joules law of heating,
H = I*I*R*t = 1 * 1 * 4 * 5 = 20 J
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