Question

in a election candidate A has secured 12% votes more than candidate B . How much % has candidate B secured less than candidate A

Answer 1

let the percent secured by candidate B is =×%
so the% secured bu candidate A = 12+×%

total votes =12+x+x=100%

=2x=100-12

=x=88/2

x=44% (candidate B)

x+12=44+12 =56% (candidate A)

Answer 2

Candidate B has secured 7.69% less than candidate A

Step-by-step explanation:

Let the no. of votes secured by candidate B be x

We are given that candidate A has secured 12% votes more than candidate B

Candidate A secured votes= $x+\frac{x}{12}=\frac{13}{12}x$

Difference in votes =$\frac{13}{12}x-x=\frac{1}{12}x$

% has candidate B secured less than candidate A = $\frac{\frac{1}{12}x}{\frac{13}{12}x} \times 100=7.69\%$

Hence Candidate B has secured 7.69% less than candidate A

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A salary is 40% of B salary and B salary is 25% of C salary. what is the percentage of C salary is A salary​

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