Question

In a electrical line having potential difference of 220V, A bulb is connected. if electric current of 0.5 Ampere is passing through the bulb then what is the power of the bulb?​

Answer 1

Answer:

• $110 \:Watts$

Explanation:

$Given:-$

• Potential Difference (V) = 220 V

• Current (I) = 0.5 A

$ToFind:-$

• Power of the bulb

$Solution :-$

$\boxed{P = V \times I}$

Where,

• P = Power

• V = Potential Difference

• I = Current

$\implies \:\: Power =\: 220 \times 0.5$

$\implies \:\:Power =\: 220 \times \dfrac{5}{10}$

$\implies \:\: Power =\: 22 \times 5$

$\implies \:\:Power =\: 110\: Watts$

$\therefore$ The power of the bulb is 110 Watts.

Answer 2

Answer:

Power = 110 Watt

Explanation:

Given = potential difference,V = 220

= current = 0.5A = 1/2A

We know that,

Power = VI

= 220 *1/2

= 110 Watt