Question

In a electrical line having potential difference of 220Volts,a bulb is connected. if electric current of 0.5 Ampere is passing through the bulb then what is the power of the bulb?
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Answer 1

Answer :-

Power of the bulb is 110 W .

Explanation :-

We have :-

• Potential difference = 220 V

• Current = 0.5 A

To find :-

• Power of the bulb.

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⇒ P = i²R

⇒ P = i × i × R

⇒ P = Vi [ ∵ V = iR ]

Where :-

• P is the power.

• V is potential difference.

• i is current.

Substituting values, we get :-

⇒ P = 220(0.5)

⇒ P = 110 W

Answer 2

Answer:

Given :-

• In a electrical line having potential difference of 220 V.
• A bulb is connected if electric current of 0.5 A is passing through the bulb.

To Find :-

• What is the power of the bulb.

Formula Used :-

$\longmapsto\sf\boxed{\bold{\pink{P =\: V \times I}}}$

where,

• P = Power
• V = Potential Difference
• I = Current

Solution :-

Given :

• Potential Difference (V) = 220 V
• Current (I) = 0.5 A

According to the question by using the formula we get,

$\implies \sf Power =\: 220 \times 0.5$

$\implies \sf Power =\: 22{\cancel{0}} \times \dfrac{5}{1\cancel{0}}$

$\implies \sf Power =\: 22 \times 5$

$\implies \sf\bold{\red{Power =\: 110\: Watts}}$

$\therefore$ The power of the bulb is 110 Watts.