Math, asked by Pranjal8330, 5 months ago

In a equilateral triangle A,B,CD is a point on side BC such that BD=1/3prove that 9ADsquar=7ABsquare

Answers

Answered by drishtisingh156
1

ABC is an Equilateral triangle such that,

AB=BC=AC

Construction:

Draw an Altitude AE such that,

E lies on BC and

AE perpendicular to BC

In △AEB

By Pythagoras Theorem,

AB

2

=AE

2

+EB

2

.....(1)

In △AED

By Pythagoras Theorem,

AD

2

=AE

2

+ED

2

.....(2)

From 1) and 2)

AD

2

=ED

2

+AB

2

−EB

2

.....(3)

Since, EB=

2

1

BC=

2

AB

=

6

3AB

and

ED=

6

BC

=

6

AB

∴ AD

2

=

36

AB

2

+AB

2

36

9AB

2

∴ 9AD

2

=7AB

2

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Answered by manaswimore9
0

Answer:

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