Question

in a equilateral triangle of side 3√3 find the length of the altitude​

Answer 1

Answer:

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Answer 2

≡QUESTION≡

In an equilateral triangle of side 3√3 cm, find the length of the altitude.

                                                                                         

║⊕ANSWER⊕║

GIVEN

Side of an equilateral ∆ABC= 3√3 cm.

AB = AC = BC = 3√3 cm

Let AD = h (Altitude)

BD = ½ BC( ALTITUDE BISECTS THE BASE)

BD = ½(3√3)

     = 3√3/2 cm

AB² = AD²+ BD²

(3√3)² = h² + (3√3/2)²

27 = h² + 27/4

h² = 27 - 27/4

h² = (27×4 -27)/4

h²= (108 -27)/4

h²= 81/4

h=√(81/4)

h= 9/2

 = 4.5 cm

∴ Altitude of the equilateral triangle is 4.5 cm