In a equilateral triangle, prove that three times the square of one of its altitudes.
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△ABC is an Equilateral Triangle.
AB=BC=AC
CD Perpendicular to AB
To Prove:
3AC2=4CD2
Proof:
In △ADC
By Pythagoras Theorem,
AC2=AD2+DC2.....(1)
In △BDC
By Pythagoras Theorem,
BC2=DC2+BD2.....(2)
Adding 1) and 2) We get,
2AC2=2DC2+AD2+BD2 (SinceAC=BC)
Since, AD=BD=21AC (SinceAC=AB)
∴ 2AC2=2DC2+21AC2
∴ 2AC2−21AC2=2DC2
∴ 3AC2=4CD2
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