In a equilateral triangle the
in radius circum radius and one of the ex radii are in the ratio
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Given:
Case of Equilateral Triangle and
Angle A = Angle B= Angle C = 60° and
When a triangle is circumscribed in a circle the circum radius be 'R' and one ofthe external radius as r.
But-:
R = r (as they are the same radius)
So-:
To find out the ratio between the circum radius and the external radius we can use the formula for external radius.
The formula of external radius is
=> 4*RSinA/2*cosB/2*cosC/2
On putting all the values-:
=> 4R*sin 60/2*cos 60/2*cos 60/2
=> 4R*1/2*(3^1/2)/2*(3^1/2)/2
=> 3/2R
Now the resulting ratio we get is -:
=> R:3/2R
=> (2:3)
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