Question

in a examination, a student has score 33% marks to pass, He gets 40 marks and fails by 26 marks. Find the maximum number of marks. ​

Answer 1

Answer:

200 marks

Step-by-step explanation:

let the maximum marks in examination be = 100

then for passing it will be needing 33% of marks

But for passing marks required are 40+26=66

and 33%of marks are required if the maximum marks should be 100

So 66 marks are required to pass

Maximum marks = 100×66/33= 200marks

Answer 2

Given :

▪︎ Percentage of passing mark in exam = 33 %

▪︎A student got 40 marks but fail by 26 marks

To find :

The maximum mark of the examination

Concept :

To find the maximum marks . See , the percentage of passing marks and the total passing marks .

Use the formula to find the maximum marks -:

$\boxed{M=\dfrac{100}{Pp}×P}$

Where,

M = Maximum marks

Pp = Percentage of passing marks

P = Passing marks

_________________________________

So , first find the passing marks:

$P = 40+26\:marks$

$P=66\:marks$

So , the passing marks is 66 . Now , find the maximum marks .

Solution :

$:\implies{M=\dfrac{100}{33}×66}$

$:\implies{M=\dfrac{100}{1}×2}$

$:\implies{M=100×2}$

$:\implies{M=200\:marks}$

Answer :

So , the maximum marks of the examination is 200 marks.