in a examination, a students must get 36 percent marks to pass . jayant get 180 marks and fail by 3.6
marks find the maximum mark
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let X be a maximum marks
X × 36/ 100 = 180 + 3.6
X × 9/25 = 183.6
X = 1836×25 / 9 × 10
X = 204×25/10
X = 204×5/2
X = 102× 5 = 510
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