In a face-centered cubic lattice how many atoms are contained in a unit cell
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in fcc half of a atom is present at each face and 1/8 of atoms at each corner
so it have total
= 1/2×6+1/8×8
=3+1
= 4 atoms
so it have total
= 1/2×6+1/8×8
=3+1
= 4 atoms
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