Question

In a face centred lattice of x and y ,x atoms are present at the corners while y atoms are at face centres.then tha formula of the compound would be if two atoms of x are missing from the corners

Answer 1

x= 6/8=3/4 , y=6/2=3 ans= x3 y12

Answer 2

Given:

Unit cell = Face centered

X atoms located at corners

Y atoms located at face centers

Solution:

No. of atoms of X from corners of unit cell = $\frac{7}{8}$

(Because, as atoms X are present only in 7 corners it will be = 7×$\frac{1}{8}$ = $\frac{7}{8}$)

No. of atoms of Y from faces of unit cell = 3 (∵standard value for face centered cell)

As to find the formula of the compound, the ration of atom X and Y is to be calculated

∴ X :  Y

$\frac{7}{8} = 3$

7 = 24

Thus the value of X is 7, whereas Y is 24.

Conclusion:

The formula of the compound would be $X_7Y_{24}$.

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