Question

In a factory 10 buls of 50 W each and 5 fans of 70 W each operate for 12 hours daily.calculate the units of elecy consumed.also find the total expenditure if 1 units costs rupees 2

Answer 1

1 bulb power= 50W
so, 10 bulbs = 10*50=500W

1 fan power= 70W
so, 5 fans = 70*5=350W

both the appliances are operated for the same time
total power = 500+350
                  = 850W
                   = 850/1000 kW

Time = 12 hours

units of electricity = power * time (it is actually kW*t)
                             = 850/1000 * 12
                             =17/5 * 3
                             =3.4 * 3
                             =10.2 kWh

1 unit = Rs.2
so, 10.2 kWh = 10.2 * 2
                      = Rs.20.4 

If there's any mistake pls inform in the comment

Answer 2

Answer:  = Rs.20.4  

Explanation:

1 bulb power= 50W

so, 10 bulbs = 10*50=500W

1 fan power= 70W

so, 5 fans = 70*5=350W

both the appliances are operated for the same time

total power = 500+350

                 = 850W

                  = 850/1000 kW

Time = 12 hours

units of electricity = power * time (it is actually kW*t)

                            = 850/1000 * 12

                            =17/5 * 3

                            =3.4 * 3

                            =10.2 kWh

1 unit = Rs.2

so, 10.2 kWh = 10.2 * 2

                     = Rs.20.4