Question

In a factory 10 buls of 50 W each and 5 fans of 70 W each operate for 12 hours daily.calculate the units of elecy consumed.also find the total expenditure for 1 month if 1 units costs rupees 2​

Answer 1

Answer:

1 bulb power=50W

so, 10bulb =10*50W=500W

1 fan power=70W

so, 5 fans=70*5=350W

both the application are operated for the same time

total power=500+350

=850W

=850/1000 kW

time=12hour

units of electricity= power *time(it is actually kW*t)

=850/1000*12

=17/5*3

=34*3

=10.2kWh

1 unit=RS.2

so,10.2 kWh= 10.2*2

=Rs 20.4

If there's any mistake please inform in the comment