in a factory 600men had provisions for 180 days 100men left at the fort food will last for
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Answered by
8
Heya
this is your answer....
It is given that
> If there will be 600 men then food so last for 180 days.
But 100 men left. so we have to obtain
how many days will the did last for....
Now men will be 500.
As there will be more men food will last for less days. if there will be less men food will last for more days.
So,. It is a case of inverse Proportion.
In case of inverse Proportion.
x1 × y1 = x2 × y2
600 × 180 = 500 × y2.
= 6 × 36
= 216.
Hence. if 100 men leave at the first day then the food will last for 216 days.
Hope it helps
this is your answer....
It is given that
> If there will be 600 men then food so last for 180 days.
But 100 men left. so we have to obtain
how many days will the did last for....
Now men will be 500.
As there will be more men food will last for less days. if there will be less men food will last for more days.
So,. It is a case of inverse Proportion.
In case of inverse Proportion.
x1 × y1 = x2 × y2
600 × 180 = 500 × y2.
= 6 × 36
= 216.
Hence. if 100 men leave at the first day then the food will last for 216 days.
Hope it helps
Tigamshu:
how you make things in fraction
Answered by
5
Provisions available : for 180 days for 600 men.
Let us find out how many days the provisions will last for just one man. We just multiply.
So at the fort, there are provisions (food) for 600 * 180 days for one man.
If 100 persons left the factory, then 500 men are still there.
So the provisions will last for 600 * 180 / 500 = 216 days.
Let us find out how many days the provisions will last for just one man. We just multiply.
So at the fort, there are provisions (food) for 600 * 180 days for one man.
If 100 persons left the factory, then 500 men are still there.
So the provisions will last for 600 * 180 / 500 = 216 days.
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