In a factory, an electric bulb of 500W is used for 2 hours and an electric motor 0f 0.5 HP is used for 5 hours daily. Calculate the cost of using the bulb and motor for April if the rate of electrical energy is Rupees 3 per unit. (1 HP = 746 W)
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Electricity per unit is charge per Kilowatt:
Daily usage for the two is:
Bulb = 500W x 2 = 1000W
Electric motor: 746/0.5 x 5 = 1865W
Total daily wattage = 1865W+1000 =2865W per day
Month of April has 30 days,
Therefore wattage for the 30 days= (2865 x 30)W
= 85950W
Convert to Kilowatts.... divide by 1000
85950/1000= 85.95 Kw
If 1 Kw= Rs. 3
Then 85.95= 3x85.95/1 = Rs. 257.85
Rupees 257.85
Daily usage for the two is:
Bulb = 500W x 2 = 1000W
Electric motor: 746/0.5 x 5 = 1865W
Total daily wattage = 1865W+1000 =2865W per day
Month of April has 30 days,
Therefore wattage for the 30 days= (2865 x 30)W
= 85950W
Convert to Kilowatts.... divide by 1000
85950/1000= 85.95 Kw
If 1 Kw= Rs. 3
Then 85.95= 3x85.95/1 = Rs. 257.85
Rupees 257.85
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