Math, asked by mohdaaish8562, 1 year ago

In a factory men,women and children were employed in the ratios of 8:5:1 to finish a job and their individual wages were in the ratio 5:2:3 .Total daily wages of all amounts to rs 318.Find the total daily wages paid to each category?pls reply soon

Answers

Answered by harshit02122004
22
wage given to men is 5a
wage given to women is 2a
wage given to children is 3a
5a + 2a + 3a= 318
10a = 318 \\ 318 \div 10 = a
Therefore 31.8=a
Therefore,
wage given to men are 5a=
5a = 31.8 \times 5 \\ 5a = 159
what given to women are 2a=
2a = 2 \times 31.8 \\ 2a = 63.6
wage given to children are 3a=
3a = 3 \times 31.8 \\ 3a = 95.4

Please mark it as brainliest
Answered by LORDxxVOLDEMORT
5

Answer:

wage given to men is 5a  

wage given to women is 2a  

wage given to children is 3a

Therefore 31.8=a

Therefore,

wage given to men are 5a=

what given to women are 2a=

wage given to children are 3a=


Step-by-step explanation:


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