Question

) In a factory of 140 machine parts, 5 percent were
defective. In a factory of 80 machine parts, 10
percent were defective. For the two factory
combined, what percent of the machine parts were
defective?
A. 6.50%
B. 7%
C. 7.50%
D. 8%​

Answer 1

Answer:

Step-by-step explanation:

140×5/100= 7

80×10/100= 8

(100×15)÷ 220 = 6.81

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

In a factory of 140 machine parts, 5 percent were defective. In a factory of 80 machine parts, 10 percent were defective. For the two factory combined, what percent of the machine parts were defective

A. 6.50%

B. 7%

C. 7.50%

D. 8%

EVALUATION

Here it is given that in first factory of 140 machine parts, 5 percent were defective

So total number of defective parts in first factory

$\displaystyle \sf{ = 140 \times \frac{5}{100} }$

$\displaystyle \sf{ =7 }$

In second factory of 80 machine parts, 10 percent were defective.

So total number of defective parts in second factory

$\displaystyle \sf{ = 80 \times \frac{10}{100} }$

$\displaystyle \sf{ = 8 }$

Now for the two factory combined

Total number of machine parts

= 140 + 80

= 220

Total number of defective parts

= 7 + 8

= 15

Hence the required percentage

$\displaystyle \sf{ = \frac{15}{220} \times 100\% }$

$\displaystyle \sf{ = 6.8\% }$

$\displaystyle \sf{ \approx \: 7\% }$

FINAL ANSWER

Hence the correct option is B. 7%

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