in a factory the production of cycles rose to 48400 from 40000 in 2 years . Find the rate of growth per annum if it was uniform during 2 years plz answer fast
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Answered by
49
Increased growth in 2 year=48400-40000
A=p(1+r/100)n
48400=40000(1+r/100)^2
48400/40000=(1+r/100)^2
121/100=(1+r/100)^2
(11/10)^2=(1+r/100)^2
When powers are same, then
11/10=1+r/100
11/10-1=r/100
11-10/10=r/100
1/10=r/100
R=1/10×100
=10%
A=p(1+r/100)n
48400=40000(1+r/100)^2
48400/40000=(1+r/100)^2
121/100=(1+r/100)^2
(11/10)^2=(1+r/100)^2
When powers are same, then
11/10=1+r/100
11/10-1=r/100
11-10/10=r/100
1/10=r/100
R=1/10×100
=10%
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11
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