Math, asked by sahilsinghjosan, 5 months ago

in a factory the production of machines rose to 48400 from 40000 at 10 %p.a fimd the time period​

Answers

Answered by rajnibisht524
0

Answer:

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Answered by rajireddymuskula5
1

Answer:

the time was taken is 2 years.....

Step-by-step explanation:

The production of cycles rose to 48,400 from 40,000 in 2 years

⇒ Present production = 40,000

⇒ After two years = 48,000

⇒ Time = 2 years

⇒ Rate of increasement = ?

According to the question,

Production after 2 years

= Present production(1+R100)t

⇒48,400 = 40,0000 (1+R1002)

⇒484400=(1+R100)2

⇒1+R1002220

⇒R100=110

⇒R=10%

⇒Rate of increasement = 10%

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