Question

In a factory the production of motor bikes was 40000 in a prticular year ,which rose to 48400 in two years .find the rate of growth per annum ,if it aws uniform during two years.

Answer 1

increased growth in year = 48400-40000=8400₹
rate of growth is =
increased growth = begging production×r×time/100
8400 = 40000×r×2/100
r = 840000/80000 = 10.5 % p.a.

Answer 2

Answer:

The rate of interest is 10%.    

Step-by-step explanation:

Given : In a factory the production of motor bikes was 40000 in a particular year, which rose to 48400 in two years.

To find : The rate of growth per annum?

Solution :

Using the compound interest formula,

$A=P(1+\frac{r}{100})^t$

Where, A is the amount A=Rs.48400

P is the principal P=Rs.40000

t is the time t=2 years

r is the rate of interest.

Substitute the values in the formula,

$48400=40000(1+\frac{r}{100})^2$

$\frac{48400}{40000}=(1+\frac{r}{100})^2$

$1.21=(1+\frac{r}{100})^2$

Taking root both side,

$\sqrt{1.21}=\sqrt{(1+\frac{r}{100})^2}$

$1.1=1+\frac{r}{100}$

$1.1-1=\frac{r}{100}$

$0.1=\frac{r}{100}$

$0.1\times 100=r$

$10=r$

Therefore, The rate of interest is 10%.