Question

in a factory the provision of a motorbike was 40000 in a particular year which goes to 48400 in 2 years find the rate of growth per annum if it was uniform during 2 year

Answer 1

N' = N (1 + r/100)^2

48400 = 40000 (1 + r/100)^2

Shifting 40000 to other side

121 / 100 = (1 + r/100)^2

Taking square root both sides

11/10 = 1+r/100

r/100 = 1/10

So r = 10%