Math, asked by keerthanahc, 5 hours ago

In a family get together if one out of every three guests brought bouquets, one out of five
guests brought gift items, one out of six gave cash gifts and the remaining 27 guests gave
gift vouchers and none of them gave two things. How many people attended the party?

Answers

Answered by shardakuknaa
1

Answer:

ANSWER

Dear Student,

◆ Answer -

90 guests

● Explanation -

Let x be total no of guests who attended the party.

No two guests gave two things.

Guests bringing bouquets = x/3

Guests bringing gift items = x/5

Guests bringing cash gifts = x/6

Guests bringing gift vouchers = 27

So now, total guests are calculated as -

x = x/3 + x/5 + x/6 + 27

x = 10x/30 + 6x/30 + 5x/30 + 27

x = 21x/30 + 27

x - 7x/10 = 27

3x/10 = 27

x = 27 × 10/3

x = 90 guests

Therefore, 90 people attended the party.

Thanks dear. Hope this helps you..

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