Question

in a family of 3 childens , find the probability of having atleast 1 boy

Answer 1

Probability of at least 1 boy is = Probability of one Boy + Probability of two Boys + Probability of all three Boys

Probability of all three Boys = (1/2)*(1/2)*(1/2) = 1/8

Probability of two Boys = (1/2)*(1/2) = 1/4

Probability of one Boy = 1/2

Probability of at least one boy = 1/2 + 1/4 + 1/8 = 7/8

.$\boxed{THANKS}$
$\boxed{Follow\:me}$