In a family of 3 children calculate the probability of having at least one boy please ellaborate
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Answer :-
=}Total children= 3
=} P(a boy)= 1/3
sachinanandharpeem9k:
you r wrong
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number of sample space =3
p(atleast one boy)=probability of one boy +probability of two boy +probability of 3 boy
Probability of all three Boys = (1/2)*(1/2)*(1/2) = 1/8
Probability of two Boys = (1/2)*(1/2) = 1/4
Probability of one Boy = 1/2
Probability of at least one boy = 1/2 + 1/4 + 1/8 = 7/8
p(atleast one boy)=probability of one boy +probability of two boy +probability of 3 boy
Probability of all three Boys = (1/2)*(1/2)*(1/2) = 1/8
Probability of two Boys = (1/2)*(1/2) = 1/4
Probability of one Boy = 1/2
Probability of at least one boy = 1/2 + 1/4 + 1/8 = 7/8
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