In a family of 3 children, find probability of having at least one boy.
Answers
Answered by
2
Answer:
Step-by-step explanation:
At least means not less than.
Hence we want the probability of getting not less than one boy.
This is :
P(one boy) or P(a boy and a boy ) or P(a boy and a boy and a boy)
1/3 + (1/3 × 1/3) + (1/3 × 1/3 × 1/3)
= 1/3 + 1/9 + 1/27 = 13/27
= 13/27
Answered by
2
Answer:
Step-by-step explanation:
At least means not less than.
Hence we want the probability of getting not less than one boy.
This is :
P(one boy) or P(a boy and a boy ) or P(a boy and a boy and a boy)
1/3 + (1/3 × 1/3) + (1/3 × 1/3 × 1/3)
= 1/3 + 1/9 + 1/27 = 13/27
= 13/27
Step-by-step explanation:
At least means not less than.
Hence we want the probability of getting not less than one boy.
This is :
P(one boy) or P(a boy and a boy ) or P(a boy and a boy and a boy)
1/3 + (1/3 × 1/3) + (1/3 × 1/3 × 1/3)
= 1/3 + 1/9 + 1/27 = 13/27
= 13/27
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