In a family of 3 children . find the probability of having at least one boy
Answers
Answered by
3
Hi!
Answer-
The probability that each child will be a boy is 1/2.
The probability that each child will be a girl is 1/2.
The probability of no. boys = 1/2 × 1/21/2 = 1/8
The probability of at least 1 boy = 1 - the probability of no boys.
= 1 - 1/8 = 7/8
•OR•
The number of the possibilities is shown below
Probability of 0 boys = 1/8
Probability of 1 boy = 3 × 1/8 = 3/8
Probability of 2 boys = 3 × 1/8 = 3/8
Probability of 3 boys = 1/8
The probability of at least 1 boy is equal to the probability of 1 or 2 or 3 boys which = 3/8 + 3/8 + 1/8 = 7/8.
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•Stargazerr•
Answer-
The probability that each child will be a boy is 1/2.
The probability that each child will be a girl is 1/2.
The probability of no. boys = 1/2 × 1/21/2 = 1/8
The probability of at least 1 boy = 1 - the probability of no boys.
= 1 - 1/8 = 7/8
•OR•
The number of the possibilities is shown below
Probability of 0 boys = 1/8
Probability of 1 boy = 3 × 1/8 = 3/8
Probability of 2 boys = 3 × 1/8 = 3/8
Probability of 3 boys = 1/8
The probability of at least 1 boy is equal to the probability of 1 or 2 or 3 boys which = 3/8 + 3/8 + 1/8 = 7/8.
Plz mark as Brainliest!
Happy to help :)
•Stargazerr•
Answered by
7
Answer:
Step-by-step explanation:
Total number of children = 3.
All three are boys = (1/2) * (1/2) * (1/2) = 1/8
Only 2 are boys = (1/2) * (1/2) = 1/4
Only 1 is boy = (1/2)
Required probability will be :
=> 1/8 + 1/4 + 1/2
=> 7/8
Therefore, it will be 7/8.
#BeBrainly
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