In a family of 3 children, find the probability of having at least one boy
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The probability that each child will be a boy is 1/2. The probability that each child will be a girl is 1/2. The probability of at least 1 boy = 1 - the probability of no boys. boys which = 3/8 + 3/8 + 1/8 = 7/8.
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Answer:
Children = 3
The probability of at least one boy = 1\3
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