in a family of 3 children find the probability of having at least one boy
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the answer of questions is 7/8
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Answer:
7/8
Step-by-step explanation:
Probability of at least 1 boy is = Probability of one Boy + Probability of two Boys + Probability of all three Boys
Probability of all three Boys = (1/2)*(1/2)*(1/2) = 1/8
Probability of two Boys = (1/2)*(1/2) = 1/4
Probability of one Boy = 1/2
Probability of at least one boy = 1/2 + 1/4 + 1/8 = 7/8
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