Question

In a family of four, the average age is 20. The parents’ age difference is 6 and the siblings’ age difference is 4. If the ages of the eldest and youngest member differ by 33, find the age of the youngest member of the family.

Solution:

Let the age of the parents be x and x+6.

Let the age of the siblings be y and y+4.



x+6-y=33

(x+x+6+y+y+4)/4 = 20



Solving the equations, y=4​

Answer 1

Answer

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