In a family of three children find the probability of having at least two boys
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In a family of the children, the possible cases are
M,M,M
M,M,F
M,F,M
M,F,F
F,M,M
F,M,F
F,F,M
F,F,F
NOTE :M means male and F means female...
Now, the probability of having at least two boys is
4/8=1/2
It is similar to the the example of the coins tossed once...
Hope it helps...
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All the best
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