In a family of three children, find the probability of having at least two
boys.
Answers
Answered by
2
Answer:
i can't understand pls send a photo or write properly
Answered by
0
Answer:
0.25
Step-by-step explanation:
Total outcomes = n(A) = 2^n = 2^3 = 8 (2 possible outcomes for each case)
Favorable outcomes = n(E) = 2 [ (B, B, G) or (B, B, B)]
p(E) = n(E)/n(A)
= 2/8
= 1/4
= 0.25
Similar questions