in a family of three children the probability of having at least one boy is
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probability = no .of observation/ total no. of conclusion
=1/3
=1/3
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number of favourable outcome to E=1
total number of possible outcomes =3
P (E)=number of favourable outcome / total number of possible outcome
P (E)=1/3
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total number of possible outcomes =3
P (E)=number of favourable outcome / total number of possible outcome
P (E)=1/3
●●● hope you got ur ans ●●●
■■■■■ Thanks ■■■■■
keep smiling
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