Question

In a family there are 4 children.Find the probability that all of them will have different birthdays.

Answer 1

$p(4) = \frac{365}{365} \times \frac{364}{365} \times \frac{363}{365} \times \frac{362}{365} \\ 0.9836$

Answer 2

◆Probability that they have birthday on diffrent days=1-probability on same day.

= P(required)=
$1 - \frac{1}{365}$

=
$p = \frac{364}{365}$
hope it will help you.