In a family there are five children namely A, B, C, D and E. Each of them was born at the interval of 5 years. Now the sum of their ages is 75. Find the age of the youngest child.
Answers
Given :
In a family there are five children namely A, B, C, D and E. Each of them was born at the interval of 5 years. Now the sum of their ages is 75.
- To find : The age of the youngest child.
Solution :
There are 5 members in a family namely A, B, C, D and E .
- Conditions
★ Each of them was born at the interval of 5 years
★ Now the sum of their ages is 75.
- Now as per given conditions
Let us consider their ages be x
→ x = A, (x + 5) = B, (x + 10) = C, (x + 15) = D and (x + 20) = E
→ x + (x + 5) + (x + 10) + (x + 15) + (x + 20) = 75
→ 5x + 50 = 75
→ 5x = 75 - 50
→ 5x =25
→ x = 25/5 = 5
•°• The age of youngest child is 5 years
Given :-
In a family there are five children namely A, B, C, D and E. Each of them was born at the interval of 5 years. Now the sum of their ages is 75
To Find :-
Age of youngest child
Solution :-
Let
Age of A = a
Age of B = a + 5
Age of C = a + 5 + 5 = a + 10
Age of D = a + 5 + 5 + 5 = a + 15
Age of E = a + 5 + 5 + 5 + 5 = a + 20
a + a + 5 + a + 10 + a + 15 + a + 20 = 75
Grouping like terms
(a + a + a + a + a) + (5 + 10 + 15 + 20) = 75
5a + 50 = 75
5a = 75 - 50
5a = 25
a = 25/5
a = 5
Age of youngest child = 5 years